For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

In a common emitter amplifier of a transistor,if the ratio of the voltage gain and current amplification factor is $4$,then the ratio of the collector and base resistances is

In a $CE$ transistor,when the base current increases by $60 \mu A$,the change in base-emitter voltage is $1.2 \ V$. Then the input resistance is: (in $\Omega$)

In an $npn$ transistor, $10^{10}$ electrons enter the emitter in $10^{-6} \; s$. If $4\%$ of the electrons are lost in the base, the current transfer ratio $(\alpha)$ will be:

The current gain for a transistor working as a common base amplifier is $0.96$. If the emitter current is $7.2 \,mA$, then the base current is (in $\,mA$)

In a common emitter transistor amplifier circuit,the input resistance is $1.8 \text{ k}\Omega$ and the output is obtained across a load resistance of $9 \text{ k}\Omega$. The alternating current gain is $70$. Corresponding to an a.c. input voltage of $6 \text{ mV}$,the output voltage will be: (in $\text{ V}$)