A transistor is connected in common emitter c | vedclass

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(C) Given:Collector resistance $R_C = 1000 \, \Omega$Voltage drop across collector resistor $\Delta V_C = 0.6 \, V$Current gain $\beta = 24$The collec

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$25$

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(C) Given:Collector resistance $R_C = 1000 \, \Omega$Voltage drop across collector resistor $\Delta V_C = 0.6 \, V$Current gain $\beta = 24$The collector current $I_C$ is given by Ohm's law:$I_C = \frac{\Delta V_C}{R_C} = \frac{0.6 \, V}{1000 \, \Omega} = 0.6 	imes 10^{-3} \, A = 6 	imes 10^{-4} \, A$The relationship between collector current $I_C$ and base current $I_B$ is:$I_C = \beta 	imes I_B$Therefore,the base current $I_B$ is:$I_B = \frac{I_C}{\beta} = \frac{6 	imes 10^{-4} \, A}{24} = 0.25 	imes 10^{-4} \, A$Converting to microamperes $(\mu A)$:$I_B = 0.25 	imes 10^{-4} 	imes 10^6 \, \mu A = 25 \, \mu A$.

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