$A$ truck of mass $30,000 \ kg$ moves up an inclined plane of slope $1$ in $100$ at a speed of $30 \ km/h$. The power of the truck is ................. $kW$ (given $g = 10 \ m/s^2$).

$A$ block of mass $m$ is released from rest at point $A$ on an inclined plane of angle $\theta$ with the vertical. The block slides down and compresses a spring of spring constant $k$. Find the compression in the spring when the speed of the block is maximum.

What is the minimum value of $F$ needed so that the block of mass $M$ begins to move upward on a frictionless inclined plane as shown?

As shown in the figure,an iron block $A$ of volume $0.25 \ m^3$ is attached to a spring $S$ of unstretched length $1.0 \ m$ and hanging from the ceiling. The spring gets stretched by $0.2 \ m$. This block is removed and another iron block $B$ of volume $0.75 \ m^3$ is now attached to the same spring and kept on a frictionless inclined plane of $30^{\circ}$ inclination. The distance of the block from the top along the incline at equilibrium is (in $m$)

$A$ solid sphere,a hollow sphere,and a ring are released from the top of a frictionless inclined plane,causing them to slide down the plane. For which object is the acceleration down the plane the maximum?

Two smooth inclined planes $A$ and $B$ each of height $20 \ m$ have angles of inclination $30^{\circ}$ and $60^{\circ}$ respectively. If $t_1$ and $t_2$ are respectively the times taken by two blocks to reach the bottom of the planes $A$ and $B$ from the top,then $t_1 - t_2 = $ (Acceleration due to gravity $= 10 \ m \ s^{-2}$)