$A$ vertical spring with force constant $K$ is fixed on a table. $A$ ball of mass $m$ at a height $h$ above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance $d$. The net work done in the process is

  • A
    $mg(h + d) + \frac{1}{2}Kd^2$
  • B
    $mg(h + d) - \frac{1}{2}Kd^2$
  • C
    $mg(h - d) + \frac{1}{2}Kd^2$
  • D
    $mg(h - d) - \frac{1}{2}Kd^2$

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