$A$ wire $ab$ of length $l$,mass $m$,and resistance $R$ slides on a smooth,thick pair of metallic rails joined at the bottom as shown in the figure. The plane of the rails makes an angle $\theta$ with the horizontal. $A$ vertical magnetic field $B$ exists in the region. If the wire slides on the rails at a constant speed $v$,then which of the following can be correct for $B$?

  • A
    $B = \sqrt {\frac{{mgR}}{{v{l^2}\,\cos\, \theta }}} $
  • B
    $B = \sqrt {\frac{{mgR\,\sin \,\theta }}{{v{l^2}\,\cos \,\theta }}} $
  • C
    $B = \sqrt {\frac{{mgR\,\sin \,\theta }}{{v{l^2}\,{{\cos }^2}\,\theta }}} $
  • D
    $B = \sqrt {\frac{{mgR\,\sin \,\theta }}{{v{l^2}}}}$

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$(a)$ What is the instantaneous value of the $emf$ induced in the wire?
$(b)$ What is the direction of the $emf$?
$(c)$ Which end of the wire is at the higher electrical potential?

$A$ wire having mass $m$ and length $l$ can freely slide on a pair of parallel smooth horizontal rails placed in a vertical magnetic field $B$. The rails are connected by a capacitor of capacitance $C$. The electric resistance of the rails and the wire is zero. If a constant force $F$ acts on the wire as shown in the figure,then the acceleration of the wire is given by:

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