A wire has resistance 12,Omega. It is bent in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When a wire of total resistance $R = 12\,\Omega$ is bent into a circle,the wire is divided into two equal halves by any diameter.Each half of the

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) When a wire of total resistance $R = 12\,\Omega$ is bent into a circle,the wire is divided into two equal halves by any diameter.Each half of the wire will have a resistance of $R' = \frac{R}{2} = \frac{12}{2} = 6\,\Omega$.These two halves are connected in parallel between the two points on the diameter.The equivalent resistance $R_{eq}$ of two resistors $R_1$ and $R_2$ in parallel is given by $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$.Here,$R_1 = 6\,\Omega$ and $R_2 = 6\,\Omega$.Therefore,$\frac{1}{R_{eq}} = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}$.Thus,$R_{eq} = 3\,\Omega$.

$A$ wire has resistance $12\,\Omega$. It is bent in the form of a circle. The effective resistance between the two points on any diameter is equal to ................ $\Omega$.

Similar Questions

The current $I$ drawn from the $5 \text{ V}$ source will be ............... $A$.

Three resistors are connected to form the sides of a triangle $ABC$. The resistances of the sides $AB$,$BC$,and $CA$ are $40\,\Omega$,$60\,\Omega$,and $100\,\Omega$ respectively. The effective resistance between the points $A$ and $B$ in $\Omega$ will be:

For the circuit shown in the figure,the equivalent resistance between $A$ and $B$ is ............. $\Omega$.

$A$ conductor of resistance $3 \Omega$ is stretched uniformly until its length is doubled. The wire is now bent in the form of an equilateral triangle. The effective resistance between the ends of any side of the triangle in ohms is

$A$ student has $10$ resistors of resistance $r$. The minimum resistance made by him from given resistors is

Vedclass Test Series

Exam Paper Generator

Online Exam Module