According to Graham's law at a given temperat | vedclass

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(C) According to Graham's law of diffusion,the rate of diffusion $r$ is directly proportional to the pressure $P$ and inversely proportional to the sq

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$({P_A}/{P_B})({M_B}/{M_A})^{1/2}$

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(C) According to Graham's law of diffusion,the rate of diffusion $r$ is directly proportional to the pressure $P$ and inversely proportional to the square root of the molar mass $M$ of the gas.Mathematically,$r \propto \frac{P}{\sqrt{M}}$.For two gases $A$ and $B$,the ratio of their rates of diffusion is given by:$\frac{r_A}{r_B} = \frac{P_A}{P_B} 	imes \sqrt{\frac{M_B}{M_A}} = \frac{P_A}{P_B} \left(\frac{M_B}{M_A}ight)^{1/2}$

According to Graham's law at a given temperature,the ratio of the rates of diffusion ${r_A}/{r_B}$ of gases $A$ and $B$ is given by

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