According to Kepler's law,the time period of a satellite varies with its radius as:

  • A
    $T^2 \propto R^3$
  • B
    $T^3 \propto R^2$
  • C
    $T^2 \propto \frac{1}{R^3}$
  • D
    $T^3 \propto \frac{1}{R^2}$

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The mean radius of the earth's orbit around the sun is $1.5 \times 10^{11} \ m$. The mean radius of the orbit of Mercury around the sun is $6 \times 10^{10} \ m$. Mercury will revolve around the sun in:

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Match Column-$I$ with Column-$II$.
Column-$I$ Column-$II$
$(1)$ Kepler's first law $(a)$ Law of periods
$(2)$ Kepler's second law $(b)$ Law of orbits
$(3)$ Kepler's third law $(c)$ Law of areas

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Two planets move around the sun. The periodic times and the mean radii of the orbits are $T_1, T_2$ and $r_1, r_2$ respectively. The ratio $T_1/T_2$ is equal to

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