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(D) The electronic configuration of $C_2$ ($12$ electrons) is: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2$

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$C_2$ consists of $1 \sigma$ and $1 \pi$ bond

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(D) The electronic configuration of $C_2$ ($12$ electrons) is: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2$. Bond order $= \frac{1}{2}(N_b - N_a) = \frac{1}{2}(8 - 4) = 2$. Since all electrons are paired,$C_2$ is diamagnetic. $C_2^{-}$ has $13$ electrons,configuration: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^1$. It has one unpaired electron,so it is paramagnetic. In $C_2$,the two highest occupied molecular orbitals are $\pi$ orbitals,meaning $C_2$ consists of two $\pi$ bonds. Therefore,the statement that $C_2$ consists of $1 \sigma$ and $1 \pi$ bond is incorrect.

According to molecular orbital theory,which of the following statements is not correct?

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