Acetamide is treated with the following reage | vedclass

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Question

(A) The reaction that converts an amide $(-CONH_2)$ into a primary amine $(-NH_2)$ with one carbon atom less is known as the $Hofmann$ bromamide degra

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$NaOH + Br_2$

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(A) The reaction that converts an amide $(-CONH_2)$ into a primary amine $(-NH_2)$ with one carbon atom less is known as the $Hofmann$ bromamide degradation reaction.Among the given reagents,$NaOH + Br_2$ (alkaline solution of bromine) is the specific reagent used for this transformation.Acetamide $(CH_3CONH_2)$ reacts with $NaOH$ and $Br_2$ to yield methylamine $(CH_3NH_2)$.The chemical equation is: $CH_3CONH_2 + 4NaOH + Br_2 \rightarrow CH_3NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$.

Acetamide is treated with the following reagents separately. Which one of these would yield methylamine?

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Which of the following is not a usual method for the preparation of a primary amine?

Write chemical equations for the following reactions:
$(i)$ Reaction of ethanolic $NH_3$ with $C_2H_5-Cl$.
$(ii)$ Ammonolysis of benzyl chloride and reaction of amine so formed with two moles of $CH_3-Cl$.

Identify the product '$B$' in the following reaction: $CH_3 - I \xrightarrow{KCN} A \xrightarrow{Na/C_2H_5OH} B$

In the above reaction,'$X$' stands for:

Which of the following reactions is appropriate for converting acetamide to methanamine?

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