Addition of HCl to vinyl chloride (CH_2=CHCl) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The addition of $HCl$ to vinyl chloride $(CH_2=CHCl)$ follows Markovnikov's rule. According to Markovnikov's rule,the negative part of the addendu

Vedclass · Accepted Answer

Markovnikov's rule

Vedclass · Answer

(D) The addition of $HCl$ to vinyl chloride $(CH_2=CHCl)$ follows Markovnikov's rule. According to Markovnikov's rule,the negative part of the addendum $(Cl^-)$ attaches to the carbon atom of the double bond that has the fewer number of hydrogen atoms. In $CH_2=CHCl$,the $CH$ group has one hydrogen atom,while the $CH_2$ group has two. Therefore,the $Cl^-$ ion attacks the $CH$ carbon,leading to the formation of $1, 1-$dichloroethane $(CH_3-CHCl_2)$.

Addition of $HCl$ to vinyl chloride $(CH_2=CHCl)$ gives $1, 1-$dichloroethane $(CH_3-CHCl_2)$ because of:

Similar Questions

$CH_2=CH-CH_3 + HBr \to ?$ What will be the product formed?

Select the suitable reagent for the conversion shown below:

$A$ compound $X$ absorbs $2$ moles of hydrogen and $X$ upon oxidation with $KMnO_4 \mid H^{+}$ gives the products shown below:
$CH_3-CO-CH_3$,$CH_3-COOH$ and $CH_3-CO-CH_2-CH_2-COOH$.
The total number of $\sigma$ bonds present in the compound $X$ is . . . . . .

The organic compound $5-$allylcyclohex$-3-$ene$-1-$ol is reacted with cold,dilute,aqueous solution of $KMnO_4$. The total number of hydroxyl group$(s)$ $(-OH)$ present in the product is

Choose the correct option for the following reactions.

Vedclass Test Series

Exam Paper Generator

Online Exam Module