After absorbing a slowly moving neutron of ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The initial momentum of the system is $P_i \approx 0$ because the neutron is moving slowly.According to the law of conservation of linear momentum

Vedclass · Accepted Answer

$\lambda$

Vedclass · Answer

(D) The initial momentum of the system is $P_i \approx 0$ because the neutron is moving slowly.According to the law of conservation of linear momentum,the final momentum of the system must also be zero $(P_f = 0)$.Let the momenta of the two product nuclei be $P_1$ and $P_2$. Since the total momentum is zero,we have $P_1 + P_2 = 0$,which implies $P_1 = -P_2$.In terms of magnitude,$|P_1| = |P_2| = P$.The de Broglie wavelength is given by the formula $\lambda = \frac{h}{p}$,where $h$ is Planck's constant and $p$ is the momentum.Since both nuclei have the same magnitude of momentum $P$,their de Broglie wavelengths will be $\lambda_1 = \frac{h}{P}$ and $\lambda_2 = \frac{h}{P}$.Therefore,$\lambda_1 = \lambda_2 = \lambda$.

Similar Questions

The de-Broglie wavelength of a body of mass $1 \ kg$ moving with a velocity of $2000 \ m/s$ is:

The resolving power of an electron microscope is greater than the resolving power of an optical microscope because

What is the de Broglie wavelength of a nitrogen molecule in air at $300 \;K$ (in $nm$)? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature. (Atomic mass of nitrogen $= 14.0076 \;u$)

Consider an electron $(m = 9.1 \times 10^{-31} \ kg)$ confined by electrical forces to move between two rigid walls separated by $1.0 \times 10^{-9} \ m$,which is about five atomic diameters. The quantized energy value for the lowest stationary state is

$A$ proton and an $\alpha-$particle are accelerated through a potential difference of $100 \ V$. The ratio of the wavelength associated with the proton to that associated with an $\alpha-$particle is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module