After the switch is closed,the current drawn | vedclass

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(C) When the switch is closed,the $3 \ \Omega$ and $6 \ \Omega$ resistors are connected in parallel.Their equivalent resistance $R_p$ is given by:$R_p

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$3$

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(C) When the switch is closed,the $3 \ \Omega$ and $6 \ \Omega$ resistors are connected in parallel.Their equivalent resistance $R_p$ is given by:$R_p = \frac{3 	imes 6}{3 + 6} \ \Omega = \frac{18}{9} \ \Omega = 2 \ \Omega$This parallel combination is in series with the $1 \ \Omega$ resistor.Therefore,the total equivalent resistance of the circuit is:$R_{eq} = 1 \ \Omega + R_p = 1 \ \Omega + 2 \ \Omega = 3 \ \Omega$The current $i$ drawn from the $9 \ V$ battery is calculated using Ohm's law:$i = \frac{V}{R_{eq}} = \frac{9 \ V}{3 \ \Omega} = 3 \ A$

After the switch is closed,the current drawn from the battery is (in $A$)

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