Allyl cyanide contains 9sigma and 3pi bonds. | vedclass

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Question

(A) The structure of allyl cyanide is $CH_2=CH-CH_2-C \equiv N$. To calculate the total number of bonds: $1$. $CH_2=$ group: $2 \sigma$ ($C$-$H$) + $1

Vedclass · Accepted Answer

$9\sigma, 3\pi$

Vedclass · Answer

(A) The structure of allyl cyanide is $CH_2=CH-CH_2-C \equiv N$. To calculate the total number of bonds: $1$. $CH_2=$ group: $2 \sigma$ ($C$-$H$) + $1 \sigma$ ($C$-$C$) + $1 \pi$ ($C$=$C$) = $3 \sigma, 1 \pi$. $2$. $-CH=$ group: $1 \sigma$ ($C$-$H$) + $1 \sigma$ ($C$-$C$) = $2 \sigma$. $3$. $-CH_2-$ group: $2 \sigma$ ($C$-$H$) + $1 \sigma$ ($C$-$C$) = $3 \sigma$. $4$. $-C \equiv N$ group: $1 \sigma$ ($C$-$C$) + $1 \sigma$ ($C$-$N$) + $2 \pi$ ($C$-$N$) = $2 \sigma, 2 \pi$. Total: $(3+2+3+1) \sigma = 9 \sigma$ bonds and $(1+2) \pi = 3 \pi$ bonds.

Allyl cyanide contains $9\sigma$ and $3\pi$ bonds.

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