Aluminium chloride in acidified aqueous solution forms a complex $A$,in which hybridisation of $Al$ is $B$. What are $A$ and $B$,respectively?
- A$[Al(H_{2}O)_{6}]^{3+}, sp^{3}d^{2}$
- B$[Al(H_{2}O)_{4}]^{3+}, sp^{3}$
- C$[Al(H_{2}O)_{4}]^{3+}, dsp^{2}$
- D$[Al(H_{2}O)_{6}]^{3+}, d^{2}sp^{3}$
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View SolutionMatch List-$I$ with List-$II$.List-$I$ (Complex) List-$II$ (Hybridisation of central metal ion) $A$. $[CoF_6]^{3-}$ $I$. $d^2sp^3$ $B$. $[NiCl_4]^{2-}$ $II$. $sp^3$ $C$. $[Co(NH_3)_6]^{3+}$ $III$. $sp^3d^2$ $D$. $[Ni(CN)_4]^{2-}$ $IV$. $dsp^2$
Choose the correct answer from the options given below:
| List-$I$ (Complex) | List-$II$ (Hybridisation of central metal ion) |
|---|---|
| $A$. $[CoF_6]^{3-}$ | $I$. $d^2sp^3$ |
| $B$. $[NiCl_4]^{2-}$ | $II$. $sp^3$ |
| $C$. $[Co(NH_3)_6]^{3+}$ | $III$. $sp^3d^2$ |
| $D$. $[Ni(CN)_4]^{2-}$ | $IV$. $dsp^2$ |
What is the number of unpaired electrons of nickel observed in $[Ni(CN)_4]^{-2}$?
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