Among the fluorides below,the one which does not exist is
- A$XeF_4$
- B$HeF_4$
- C$SF_4$
- D$CF_4$
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Easy
View SolutionIn the preparation of compounds of $Xe$,Bartlett had taken $O_2^+PtF_6^-$ as a base compound. This is because:
Medium
View SolutionComplete hydrolysis of $XeF_4$ and $XeF_6$ gives its oxides $P$ and $Q$, respectively. Identify $P$ and $Q$.
To prepare $XeF_6$,$Xe$ and $F_2$ are mixed at $573 \ K$ and $60-70 \ bar$ in the ratio of
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