Among the following carbocations:(I) Ph_{2}st | vedclass

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(B) The stability of carbocations is determined by resonance and inductive effects.$(I)$ $Ph_{2}\stackrel{+}{C} CH_{2} Me$ is a $3^{\circ}$ benzylic c

Vedclass · Accepted Answer

$I > II > III > IV$

Vedclass · Answer

(B) The stability of carbocations is determined by resonance and inductive effects.$(I)$ $Ph_{2}\stackrel{+}{C} CH_{2} Me$ is a $3^{\circ}$ benzylic carbocation stabilized by two phenyl rings.$(II)$ $Ph CH_{2} CH_{2} \stackrel{+}{C} HPh$ is a $2^{\circ}$ benzylic carbocation stabilized by one phenyl ring.$(III)$ $Ph_{2} CH \stackrel{+}{C} HMe$ is a $2^{\circ}$ carbocation with two phenyl groups attached to the adjacent carbon, providing some inductive stabilization.$(IV)$ $Ph_{2} C(Me) \stackrel{+}{C} H_{2}$ is a $1^{\circ}$ carbocation.Comparing these, the resonance stabilization from phenyl rings is the dominant factor. The order of stability is $(I)$ > $(II)$ > $(III)$ > $(IV)$.

Among the following carbocations:
$(I)$ $Ph_{2}\stackrel{+}{C} CH_{2} Me$
$(II)$ $Ph CH_{2} CH_{2} \stackrel{+}{C} HPh$
$(III)$ $Ph_{2} CH \stackrel{+}{C} HMe$
$(IV)$ $Ph_{2} C(Me) \stackrel{+}{C} H_{2}$
The order of stability is:

Similar Questions

The correct order of the relative stability of the following carbanions is:
$I$. $HC \equiv C^{-}$
$II$. $CH_2=CH-CH_2^{-}$
$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$

Most stable carbocation is

Among the following structures,which will show the most stable enamine formation?
(Where $Me$ is $-CH_{3}$)

Among the given species,which carbocations are resonance stabilized?

In which case does the heterolysis of the carbon-chlorine bond lead to the most stable carbocation?

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Among the following carbocations:$(I)$ $Ph_{2}\stackrel{+}{C} CH_{2} Me$$(II)$ $Ph CH_{2} CH_{2} \stackrel{+}{C} HPh$$(III)$ $Ph_{2} CH \stackrel{+}{C} HMe$$(IV)$ $Ph_{2} C(Me) \stackrel{+}{C} H_{2}$The order of stability is: