Among the given compounds,choose the two that | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Upon ionization,compound $A$ ($3$-bromo$-1-$methylcyclohex$-1-$ene) loses a bromide ion to form the $1-$methylcyclohex$-2-$en$-1-$yl cation.Compou

Vedclass · Accepted Answer

$A, B$

Vedclass · Answer

(C) Upon ionization,compound $A$ ($3$-bromo$-1-$methylcyclohex$-1-$ene) loses a bromide ion to form the $1-$methylcyclohex$-2-$en$-1-$yl cation.Compound $B$ ($4$-bromo$-1-$methylcyclohex$-1-$ene) loses a bromide ion to form a secondary carbocation at the $C4$ position.This secondary carbocation undergoes a hydride shift to form the more stable allylic $1-$methylcyclohex$-2-$en$-1-$yl cation,which is the same intermediate as formed from compound $A$.Therefore,compounds $A$ and $B$ yield the same carbocation.

Among the given compounds,choose the two that yield the same carbocation on ionization.

Similar Questions

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

What is the correct order of stability for free radicals?

Which of the following is the most stable carbocation?

Determine the decreasing order of stability for the following carbocations: $(I) \ CH_3-C^+(CH_3)-CH_3$,$(II) \ CH_3-CH^+(OCH_3)$,$(III) \ CH_3-CH^+(COCH_3)$.

The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module