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(C) The stability of carbocations is increased by the $+I$ effect and hyperconjugation,and decreased by the $-I$ effect.In $CH_3-CH_2-CH_2^+$ $(d)$,th

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$d > c > b > a$

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(C) The stability of carbocations is increased by the $+I$ effect and hyperconjugation,and decreased by the $-I$ effect.In $CH_3-CH_2-CH_2^+$ $(d)$,the ethyl group provides a $+I$ effect,which stabilizes the positive charge.In $F-CH_2-CH_2^+$ $(b)$ and $Br-CH_2-CH_2^+$ $(c)$,the halogens exert a $-I$ effect,which destabilizes the carbocation.Since $F$ is more electronegative than $Br$,its $-I$ effect is stronger,making $(b)$ less stable than $(c)$.$CH_3^+$ $(a)$ is a methyl carbocation,which is less stable than primary carbocations like $(d)$ and $(c)$.Therefore,the decreasing order of stability is $d > c > b > a$.

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

Similar Questions

Provide four formulas of carbocations.

In which pair is the second ion more stable than the first?

Which of the following carbocations is expected to be most stable?

The order of stability of the following carbocations is:
$I$. $CH_2 = CH - CH_2^+$
$II$. $CH_3 - CH_2 - CH_2^+$
$III$. $C_6H_5CH_2^+$

The correct order of the relative stability of the following carbanions is:
$I$. $HC \equiv C^{-}$
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$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$

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Arrange the following cations in decreasing order of their stability:$(a)$ $CH_3^+$$(b)$ $F-CH_2-CH_2^+$$(c)$ $Br-CH_2-CH_2^+$$(d)$ $CH_3-CH_2-CH_2^+$