An LED is constructed from a p-n junction dio | vedclass

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(B) The energy of the emitted photon is given by $E = \frac{hc}{\lambda}$.Given the energy gap $E_g = 1.9\; eV$.The wavelength $\lambda$ is calculated

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$654 \;nm$

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(B) The energy of the emitted photon is given by $E = \frac{hc}{\lambda}$.Given the energy gap $E_g = 1.9\; eV$.The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{hc}{E_g}$.Using the approximation $hc \approx 1240\; eV \cdot nm$,we get:$\lambda = \frac{1240\; eV \cdot nm}{1.9\; eV} \approx 652.6\; nm$.Rounding to the nearest provided option,we get $\lambda \approx 654\; nm$.

An $LED$ is constructed from a $p-n$ junction diode using $GaAsP$. The energy gap is $1.9\; eV$. The wavelength of the light emitted will be equal to

Similar Questions

Which of the following statements is true about LEDs?

Select the correct statement.

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