An L-C circuit contains a 196 text{ pF} capac | vedclass

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(D) Given: Capacitance $C = 196 	ext{ pF} = 196 	imes 10^{-12} 	ext{ F}$.Inductance $L = 441 	ext{ } \mu	ext{H} = 441 	imes 10^{-6} 	ext{ H}$.T

Vedclass · Accepted Answer

$5.41 	imes 10^5 	ext{ Hz}$

Vedclass · Answer

(D) Given: Capacitance $C = 196 	ext{ pF} = 196 	imes 10^{-12} 	ext{ F}$.Inductance $L = 441 	ext{ } \mu	ext{H} = 441 	imes 10^{-6} 	ext{ H}$.The resonant frequency $f$ of an $L-C$ circuit is given by the formula $f = \frac{1}{2 \pi \sqrt{LC}}$.Substituting the values:$f = \frac{1}{2 \pi \sqrt{441 	imes 10^{-6} 	imes 196 	imes 10^{-12}}}$$f = \frac{1}{2 \pi \sqrt{(21^2 	imes 14^2) 	imes 10^{-18}}}$$f = \frac{1}{2 \pi 	imes 21 	imes 14 	imes 10^{-9}}$$f = \frac{1}{2 	imes 3.14159 	imes 294 	imes 10^{-9}}$$f \approx \frac{1}{1847.25 	imes 10^{-9}} \approx 0.5413 	imes 10^6 	ext{ Hz} = 5.41 	imes 10^5 	ext{ Hz}$.

An $L-C$ circuit contains a $196 \text{ pF}$ capacitor and a $441 \text{ } \mu\text{H}$ inductor. The frequency of electromagnetic radiation emitted by an antenna coupled to the $L-C$ circuit is:

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