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(C) For $LC$-oscillations,the differential equation is given by $L \frac{di}{dt} + \frac{q}{C} = 0$.Differentiating with respect to time $t$,we get $L

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reciprocal of capacitance

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(C) For $LC$-oscillations,the differential equation is given by $L \frac{di}{dt} + \frac{q}{C} = 0$.Differentiating with respect to time $t$,we get $L \frac{d^2i}{dt^2} + \frac{1}{C} \frac{dq}{dt} = 0$. Since $i = \frac{dq}{dt}$,this becomes $L \frac{d^2i}{dt^2} + \frac{1}{C} i = 0$ ... $(i)$.For a mechanical spring-block system,the equation of motion is $m \frac{d^2x}{dt^2} + kx = 0$ ... $(ii)$.Comparing equation $(i)$ and $(ii)$,we observe that the mass $m$ is analogous to inductance $L$,and the force constant $k$ is analogous to the reciprocal of capacitance,i.e.,$k \propto \frac{1}{C}$.

$LC$-oscillations are similar and analogous to the mechanical oscillations of a block attached to a spring. The electrical equivalent of the force constant of the spring is

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