An aeroplane moving horizontally with a speed of $720 \, km/h$ drops a food packet while flying at a height of $396.9 \, m$. The time taken by the food packet to reach the ground and its horizontal range are (Take $g = 9.8 \, m/s^2$):
- A$3 \, s$ and $2000 \, m$
- B$5 \, s$ and $500 \, m$
- C$8 \, s$ and $1500 \, m$
- D$9 \, s$ and $1800 \, m$
Explore More
Similar Questions
$A$ missile is fired in the horizontal direction from a height of $20\,m$ at a speed of $1000\,m/s$. At what horizontal distance from the base will the missile land?
Medium
View Solution$A$ body is projected horizontally from the top of a tower of height $180 \ m$ with a velocity of $20 \ ms^{-1}$. If acceleration due to gravity is $10 \ ms^{-2}$,then match the following:
List-$I$ (Kinematic Variable) List-$II$ (Value) $A$. Velocity of the body after $1 \ s$ (in $ms^{-1}$) $I$. $5$ $B$. Horizontal displacement of the body after $1 \ s$ (in $m$) $II$. $20$ $C$. Vertical displacement of the body after $1 \ s$ (in $m$) $III$. $10$ $D$. Vertical velocity of the body after $1 \ s$ (in $ms^{-1}$) $IV$. $22.4$
The correct answer is
| List-$I$ (Kinematic Variable) | List-$II$ (Value) |
| $A$. Velocity of the body after $1 \ s$ (in $ms^{-1}$) | $I$. $5$ |
| $B$. Horizontal displacement of the body after $1 \ s$ (in $m$) | $II$. $20$ |
| $C$. Vertical displacement of the body after $1 \ s$ (in $m$) | $III$. $10$ |
| $D$. Vertical velocity of the body after $1 \ s$ (in $ms^{-1}$) | $IV$. $22.4$ |
The correct answer is
$A$ block starts from rest at the top of a frictionless slide at a height $h_1$ above the ground. The block leaves the slide moving perfectly horizontally at a height $h_2$ above the ground. The block eventually hits the ground travelling at an angle $\theta = 30^\circ$ below the horizontal. Then:
At a height $0.4\, m$ from the ground,the velocity of a projectile in vector form is $\vec v = (6\hat i + 2\hat j)\,m/s$. The angle of projection is ...... $^o$ $(g = 10\, m/s^2)$.
Difficult
View Solution$A$ bomber plane moves horizontally with a speed of $500\, m/s$ and a bomb released from it strikes the ground in $10\, s$. The angle at which it strikes the ground is $(g = 10\, m/s^2)$.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo