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(C) The molecular weight $74$ corresponds to the formula $C_4H_{10}O$ $(12 	imes 4 + 10 	imes 1 + 16 = 74)$.Lucas reagent giving white turbidity in

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$CH_3-CH(OCH_3)-CH_2-CH_3$

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(C) The molecular weight $74$ corresponds to the formula $C_4H_{10}O$ $(12 	imes 4 + 10 	imes 1 + 16 = 74)$.Lucas reagent giving white turbidity in $5-10$ minutes indicates that the alcohol is a secondary $(2^\circ)$ alcohol.The only secondary alcohol with this formula is butan-$2$-ol $(CH_3-CH(OH)-CH_2-CH_3)$.Reaction with $Na$:$CH_3-CH(OH)-CH_2-CH_3 + Na ightarrow CH_3-CH(ONa)-CH_2-CH_3$ $(Y)$ $+ 1/2 H_2$.Reaction with $CH_3-Br$ (Williamson synthesis):$CH_3-CH(ONa)-CH_2-CH_3 + CH_3-Br ightarrow CH_3-CH(OCH_3)-CH_2-CH_3$ $(Z)$ $+ NaBr$.Thus,$Z$ is $2$-methoxybutane.

An alcohol having molecular weight $74$ gives white turbidity with Lucas reagent within $5-10$ minutes. It reacts with sodium metal to give $Y$. $Y$ reacts with $CH_3-Br$ to give $Z$. $Z$ is:

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