An alcohol on oxidation is found to give CH_3 | vedclass

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(D) The oxidation of a secondary alcohol under vigorous conditions leads to the cleavage of the $C-C$ bond adjacent to the carbonyl group formed after

Vedclass · Accepted Answer

$CH_3CH(OH)CH_2CH_2CH_3$

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(D) The oxidation of a secondary alcohol under vigorous conditions leads to the cleavage of the $C-C$ bond adjacent to the carbonyl group formed after initial oxidation to a ketone.The given products are acetic acid ($CH_3COOH$,$2$ carbons) and propanoic acid ($CH_3CH_2COOH$,$3$ carbons).This implies the original alcohol must have a total of $5$ carbon atoms with the hydroxyl group at the $C-2$ position.The structure $CH_3CH(OH)CH_2CH_2CH_3$ (pentan-$2$-ol) undergoes oxidation to break the bond between $C-2$ and $C-3$,resulting in $CH_3COOH$ and $CH_3CH_2COOH$.

An alcohol on oxidation is found to give $CH_3COOH$ and $CH_3CH_2COOH$. The structure of the alcohol is

Similar Questions

$A$ $\xrightarrow{K_2Cr_2O_7 / \text{dil. } H_2SO_4} B$ $\xrightarrow{CH_3MgI / H_2O} CH_3-C(CH_3)(OH)-CH_3$. The reactant $A$ is:

Arrange the following alcohols in decreasing order of the ease of ionization under acidic conditions.

Identify the product $B$ in the following sequence of reactions:
$CH_3-CH_2-CH_2-OH$ $\xrightarrow[623 \ K]{Al_2O_3} A$ $\xrightarrow[(ii) H_2O, \Delta]{(i) conc. H_2SO_4} B$

What is the order of reactivity of the following alcohols with halogen acids?
$(1) \ CH_3CH_2CH_2OH$
$(2) \ CH_3CH_2CH(CH_3)OH$
$(3) \ CH_3CH_2C(CH_3)_2OH$

When $Butan-2-ol$ is dehydrated using sulphuric acid,the concentration of acid and temperature needed respectively are:

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