An alkane forms isomers if the number of carb | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Structural isomerism in alkanes requires a minimum of $4$ carbon atoms to form branched structures. For $n=1$ (methane),$n=2$ (ethane),and $n=3$ (

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) Structural isomerism in alkanes requires a minimum of $4$ carbon atoms to form branched structures. For $n=1$ (methane),$n=2$ (ethane),and $n=3$ (propane),only one structural arrangement is possible. For $n=4$ (butane),two isomers exist: $n$-butane $(CH_3-CH_2-CH_2-CH_3)$ and isobutane $(CH_3-CH(CH_3)-CH_3)$. Therefore,the correct answer is $4$.

An alkane forms isomers if the number of carbon atoms is at least

Similar Questions

Petroleum mainly consists of.........

Identify all the possible monochloro structural isomers expected to be formed on free radical monochlorination of $(CH_3)_2CHCH_2CH_3$.

Iso-octane is mixed with petrol:

Identify the major product $Y$ in the following reaction sequence:
$CH_3-CH(CH_3)-CH_2-Cl$ $\xrightarrow[\text{dry ether}]{Na} X$ $\xrightarrow[\text{monobromination}]{Br_2/h\nu} Y$ (major)

Natural gas is a mixture of

Vedclass Test Series

Exam Paper Generator

Online Exam Module