An alkyl halide X (C_4H_9Br) undergoes nucleo | vedclass

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(B) The alkyl halide $X$ $(C_4H_9Br)$ undergoes $S_N2$ reaction,which implies it must be a primary alkyl halide to minimize steric hindrance. Thus,$X$

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(B) The alkyl halide $X$ $(C_4H_9Br)$ undergoes $S_N2$ reaction,which implies it must be a primary alkyl halide to minimize steric hindrance. Thus,$X$ is $n$-butyl bromide $(CH_3CH_2CH_2CH_2Br)$.When $n$-butyl bromide reacts with $Mg$ in dry ether,it forms a Grignard reagent,$n$-butylmagnesium bromide $(CH_3CH_2CH_2CH_2MgBr)$.Subsequent reaction with $D_2O$ replaces the $MgBr$ group with a deuterium atom $(D)$,resulting in $n$-butane$-1-$d $(CH_3CH_2CH_2CH_2D)$.

An alkyl halide $X$ $(C_4H_9Br)$ undergoes nucleophilic substitution by $S_N2$ reaction. The product of $X$ on reaction with $Mg/\text{dry ether}$ followed by $D_2O$ is:

Similar Questions

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