An alkyne has the molecular formula C_6H_{10} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general formula for an alkyne is $C_nH_{2n-2}$. For $C_6H_{10}$,$n=6$. $1$-alkynes have the triple bond at the terminal position,represented a

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The general formula for an alkyne is $C_nH_{2n-2}$. For $C_6H_{10}$,$n=6$. $1$-alkynes have the triple bond at the terminal position,represented as $R-C \equiv CH$. For a $6$-carbon chain,the possible structures for $1$-alkynes are: $1$. $CH_3-CH_2-CH_2-CH_2-C \equiv CH$ $(hex-1-yne)$ $2$. $CH_3-CH_2-CH(CH_3)-C \equiv CH$ $(3-methylpent-1-yne)$ $3$. $CH_3-CH(CH_3)-CH_2-C \equiv CH$ $(4-methylpent-1-yne)$ $4$. $(CH_3)_3C-C \equiv CH$ $(3,3-dimethylbut-1-yne)$ Thus,there are $4$ possible isomers for $1$-alkyne.

An alkyne has the molecular formula $C_6H_{10}$. The number of $1$-alkyne isomers (excluding stereoisomers) possible for it is

Similar Questions

The major product of the following reaction is $CH_3-C\equiv CH \xrightarrow[(ii) \ DI]{(i) \ DCl \ (1 \ equiv)}$

The homologue of ethyne is

Which of the following does not give a white precipitate with ammoniacal $AgNO_3$?

Which of the following compounds on hydration (addition of $H_2O$) with $H_2SO_4/HgSO_4/H_2O$ gives an aldehyde as the major product?

By heating a mixture of $CHCl_3$ with silver powder,the compound formed is

Vedclass Test Series

Exam Paper Generator

Online Exam Module