An alternating current of frequency $50 \,Hz$ has a peak value of $14.14 \,A$. The time taken by the alternating current to reach from zero to its maximum value and the root mean square (r.m.s.) value of the current are respectively:
- A$0.025 \,s, 5 \,A$
- B$0.005 \,s, 5 \,A$
- C$0.005 \,s, 10 \,A$
- D$0.025 \,s, 10 \,A$
Explore More
Similar Questions
For an alternating current $I = I_0 \cos(\omega t)$,what is the $rms$ value and peak value of the current?
Medium
View SolutionIf the frequency of the source $e.m.f.$ in an $ac$ circuit is $n,$ the power varies with a frequency :-
Medium
View SolutionMatch the following current $\text{r.m.s.}$ values:
$(A) \ x_0 \sin \omega t$ $(i) \ x_0$ $(B) \ x_0 \sin \omega t \cos \omega t$ $(ii) \ \frac{x_0}{\sqrt{2}}$ $(C) \ x_0 \sin \omega t + x_0 \cos \omega t$ $(iii) \ \frac{x_0}{2 \sqrt{2}}$
| $(A) \ x_0 \sin \omega t$ | $(i) \ x_0$ |
| $(B) \ x_0 \sin \omega t \cos \omega t$ | $(ii) \ \frac{x_0}{\sqrt{2}}$ |
| $(C) \ x_0 \sin \omega t + x_0 \cos \omega t$ | $(iii) \ \frac{x_0}{2 \sqrt{2}}$ |
Medium
View SolutionIf $I_1, I_2, I_3$ and $I_4$ are the respective $r.m.s.$ values of the time-varying currents as shown in the four cases $I, II, III$ and $IV$,then identify the correct relation.
Medium
View SolutionAn alternating voltage is represented as $E = 20 \sin 300t$. The average value of voltage over one cycle will be ....... $V$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo