Match the following current text{r.m.s.} valu | vedclass

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(B) $(1)$ For $x = x_0 \sin \omega t$, the peak value is $x_0$. The $	ext{r.m.s.}$ value is $\frac{x_0}{\sqrt{2}}$. Thus, $(A ightarrow ii)$.$(2)$

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$(A \rightarrow ii), (B \rightarrow iii), (C \rightarrow i)$

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(B) $(1)$ For $x = x_0 \sin \omega t$, the peak value is $x_0$. The $	ext{r.m.s.}$ value is $\frac{x_0}{\sqrt{2}}$. Thus, $(A ightarrow ii)$.$(2)$ For $x = x_0 \sin \omega t \cos \omega t = \frac{x_0}{2} \sin(2 \omega t)$, the peak value is $\frac{x_0}{2}$. The $	ext{r.m.s.}$ value is $\frac{x_0/2}{\sqrt{2}} = \frac{x_0}{2 \sqrt{2}}$. Thus, $(B ightarrow iii)$.$(3)$ For $x = x_0 \sin \omega t + x_0 \cos \omega t = x_0 \sqrt{2} \sin(\omega t + \pi/4)$, the peak value is $x_0 \sqrt{2}$. The $	ext{r.m.s.}$ value is $\frac{x_0 \sqrt{2}}{\sqrt{2}} = x_0$. Thus, $(C ightarrow i)$.Therefore, the correct matching is $(A ightarrow ii), (B ightarrow iii), (C ightarrow i)$.

$(A) \ x_0 \sin \omega t$	$(i) \ x_0$
$(B) \ x_0 \sin \omega t \cos \omega t$	$(ii) \ \frac{x_0}{\sqrt{2}}$
$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$	$(iii) \ \frac{x_0}{2 \sqrt{2}}$

Match the following current $\text{r.m.s.}$ values:
$(A) \ x_0 \sin \omega t$ $(i) \ x_0$
$(B) \ x_0 \sin \omega t \cos \omega t$ $(ii) \ \frac{x_0}{\sqrt{2}}$
$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$ $(iii) \ \frac{x_0}{2 \sqrt{2}}$

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Match the following current $\text{r.m.s.}$ values:$(A) \ x_0 \sin \omega t$$(i) \ x_0$$(B) \ x_0 \sin \omega t \cos \omega t$$(ii) \ \frac{x_0}{\sqrt{2}}$$(C) \ x_0 \sin \omega t + x_0 \cos \omega t$$(iii) \ \frac{x_0}{2 \sqrt{2}}$