An amine C_{3}H_{9}N reacts with benzene sulp | vedclass

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Question

(B) The reaction of amines with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary, secondary, and tertiary amines

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(B) The reaction of amines with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary, secondary, and tertiary amines.$1$. Primary amines $(R-NH_2)$ form a sulfonamide that is soluble in $aq. NaOH$ due to the presence of an acidic hydrogen on the nitrogen atom.$2$. Secondary amines $(R_2NH)$ form a sulfonamide that is insoluble in $aq. NaOH$ because they lack an acidic hydrogen on the nitrogen atom.$3$. Tertiary amines $(R_3N)$ do not react with benzene sulphonyl chloride.Since the given amine forms a white precipitate that is insoluble in $aq. NaOH$, it must be a secondary amine.The molecular formula $C_3H_9N$ corresponds to a secondary amine, $N$-methylethanamine $(CH_3-NH-CH_2CH_3)$.

An amine $C_{3}H_{9}N$ reacts with benzene sulphonyl chloride to form a white precipitate which is insoluble in $aq. NaOH$. The amine is

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