An angiospermic male plant with 24 chromosome | vedclass

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(D) The pollen mother cells $(PMC)$ are diploid $(2n)$ and contain $24$ chromosomes,so $2n = 24$,which means $n = 12$.Male gametes are haploid $(n)$ a

Vedclass · Accepted Answer

$24$ and $36$

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(D) The pollen mother cells $(PMC)$ are diploid $(2n)$ and contain $24$ chromosomes,so $2n = 24$,which means $n = 12$.Male gametes are haploid $(n)$ and contain $12$ chromosomes.The root cells of the female plant are diploid $(2n)$ and contain $24$ chromosomes,so $n = 12$.The female gamete is haploid $(n)$ and contains $12$ chromosomes.Syngamy involves the fusion of a male gamete $(n = 12)$ and a female gamete $(n = 12)$ to form a diploid $(2n)$ zygote,which develops into an embryo with $24$ chromosomes.Triple fusion involves the fusion of two polar nuclei $(n + n = 24)$ and one male gamete $(n = 12)$ to form a triploid $(3n)$ primary endosperm nucleus,which develops into an endosperm with $36$ chromosomes.

An angiospermic male plant with $24$ chromosomes in its pollen mother cells is crossed with a female plant bearing $24$ chromosomes in its root cells. What would be the ploidy of the embryo and endosperm respectively formed after this cross?

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