An electric oven of $2\, kW$ power rating is operated in a domestic electric circuit $(220\, V)$ that has a current rating of $5\, A$. What result do you expect? Explain.

(D) The current drawn by the electric oven can be calculated using the formula:
$P = VI$
$I = \frac{P}{V}$
Where:
$P = 2\, kW = 2000\, W$
$V = 220\, V$
$I = \frac{2000}{220} = 9.09\, A$
Since the current drawn by the oven $(9.09\, A)$ is greater than the current rating of the circuit $(5\, A)$,the circuit will experience an overload.
As a result,the fuse wire will melt due to excessive heating,and the circuit will break,preventing any damage to the appliances.