An electromagnetic wave propagating through a | vedclass

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Question

(A) For an electromagnetic wave in a vacuum,the relationship between the amplitudes of the electric field $(E_0)$ and the magnetic field $(B_0)$ is gi

Vedclass · Accepted Answer

$E_0 k = B_0 \omega$

Vedclass · Answer

(A) For an electromagnetic wave in a vacuum,the relationship between the amplitudes of the electric field $(E_0)$ and the magnetic field $(B_0)$ is given by $E_0 = c B_0$,where $c$ is the speed of light in a vacuum.We know that the speed of light $c$ is related to the angular frequency $\omega$ and the wave number $k$ by the equation $c = \frac{\omega}{k}$.Substituting this into the first relation,we get $E_0 = \left( \frac{\omega}{k} \right) B_0$.Rearranging this equation,we obtain $E_0 k = B_0 \omega$.Therefore,the correct option is $A$.

An electromagnetic wave propagating through a vacuum is described by $E = E_0 \sin(kx - \omega t)$ and $B = B_0 \sin(kx - \omega t)$. Which of the following equations is true?

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