An electromagnetic wave of wavelength 2 times | vedclass

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Question

(A) The wavelength of an electromagnetic wave in a medium is given by $\lambda_m = \frac{\lambda_0}{n}$,where $\lambda_0$ is the wavelength in vacuum

Vedclass · Accepted Answer

$1 	imes 10^{-10} \,m$

Vedclass · Answer

(A) The wavelength of an electromagnetic wave in a medium is given by $\lambda_m = \frac{\lambda_0}{n}$,where $\lambda_0$ is the wavelength in vacuum and $n$ is the refractive index of the medium.
For a non-magnetic dielectric medium,the refractive index $n$ is related to the relative permittivity $\epsilon_r$ by $n = \sqrt{\epsilon_r}$.
Given $\lambda_0 = 2 	imes 10^{-10} \,m$ and $\epsilon_r = 4$.
Therefore,$n = \sqrt{4} = 2$.
The new wavelength is $\lambda_m = \frac{2 	imes 10^{-10}}{2} = 1 	imes 10^{-10} \,m$.
Thus,the correct option is $A$.

An electromagnetic wave of wavelength $2 \times 10^{-10} \,m$ passes from vacuum into a dielectric medium of relative permittivity $4$. Then its wavelength will be

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