An electron moves with speed 2 times 10^5 m/ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The velocity of the electron is $\vec{v} = 2 	imes 10^5 \hat{i} \ m/s$. The magnetic field is $\vec{B} = (\hat{i} + 4\hat{j} - 3\hat{k}) \ T$. Th

Vedclass · Accepted Answer

$1.6 	imes 10^{-13}$

Vedclass · Answer

(C) The velocity of the electron is $\vec{v} = 2 	imes 10^5 \hat{i} \ m/s$. The magnetic field is $\vec{B} = (\hat{i} + 4\hat{j} - 3\hat{k}) \ T$. The magnetic force on a moving charge is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$. For an electron,$q = -1.6 	imes 10^{-19} \ C$. First,calculate the cross product $\vec{v} 	imes \vec{B}$: $\vec{v} 	imes \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 2 	imes 10^5 & 0 & 0 \ 1 & 4 & -3 \end{vmatrix} = \hat{i}(0) - \hat{j}(-6 	imes 10^5) + \hat{k}(8 	imes 10^5) = (6 	imes 10^5 \hat{j} + 8 	imes 10^5 \hat{k}) \ m/s \cdot T$. The force vector is $\vec{F} = -1.6 	imes 10^{-19} 	imes (6 	imes 10^5 \hat{j} + 8 	imes 10^5 \hat{k}) \ N$. The magnitude of the force is $|\vec{F}| = 1.6 	imes 10^{-19} 	imes \sqrt{(6 	imes 10^5)^2 + (8 	imes 10^5)^2}$. $|\vec{F}| = 1.6 	imes 10^{-19} 	imes \sqrt{36 	imes 10^{10} + 64 	imes 10^{10}} = 1.6 	imes 10^{-19} 	imes \sqrt{100 	imes 10^{10}}$. $|\vec{F}| = 1.6 	imes 10^{-19} 	imes 10 	imes 10^5 = 1.6 	imes 10^{-13} \ N$.

An electron moves with speed $2 \times 10^5 \ m/s$ along the positive $x$-direction in the presence of a magnetic field of induction $B = (\hat{i} + 4\hat{j} - 3\hat{k}) \ T$. The magnitude of the force experienced by the electron in newtons is (Charge on the electron $= 1.6 \times 10^{-19} \ C$)

Similar Questions

The probability of choosing randomly a number $c$ from the set $\{1, 2, 3, \ldots, 9\}$ such that the quadratic equation $x^2 + 4x + c = 0$ has real roots is

The principal section of a glass prism is an isosceles triangle $ABC$ with $AB=AC$. The face $AC$ is silvered. $A$ ray of light is incident normally on the face $AB$ and after two reflections,it emerges from the base $BC$ perpendicular to the base. Angle $BAC$ of the prism is (in $^{\circ}$)

If $A(2,-1)$ and $B(6,5)$ are two points,the ratio in which the foot of the perpendicular from $P(4,1)$ to $AB$ divides $AB$ is:

For the given figure,if the block remains in equilibrium,find the frictional force between the block and the wall in $N$.

Which of the following is not a characteristic property of chemical equilibrium?

Vedclass Test Series

Exam Paper Generator

Online Exam Module