An electron of mass $m$ and a photon have the same energy $E$. The ratio of the de-Broglie wavelengths associated with them is ($c$ = velocity of light in air).
- A$\left[\frac{E}{2m}\right]^{1/2}$
- B$\frac{1}{c}\left[\frac{E}{2m}\right]^{1/2}$
- C$c(2mE)^{1/2}$
- D$\frac{1}{c}\left[\frac{2m}{E}\right]^{1/2}$
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