An element $E$ has an ionisation enthalpy value of $374 \ kJ \ mol^{-1}$. $E$ reacts with elements $A, B, C$ and $D$ with electron gain enthalpy values of $-328, -349, -325$ and $-295 \ kJ \ mol^{-1}$,respectively. The correct order of the products $EA, EB, EC$ and $ED$ in terms of ionic character is $:$

  • A
    $EB > EA > EC > ED$
  • B
    $ED > EC > EA > EB$
  • C
    $EA > EB > EC > ED$
  • D
    $ED > EC > EB > EA$

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Similar Questions

Point out the wrong statement: On moving horizontally from left to right across a period in the periodic table

Which of the following statement$(s)$ is/are incorrect?

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State whether the following statements are true or false:
$(i)$ Higher the ionization enthalpy,lower the screening effect.
$(ii)$ The ionization enthalpy of $Be$ is higher than that of $B$.
$(iii)$ The shielding effect increases as we move from left to right in a period.
$(iv)$ The increasing order of the first ionization energy is $B < Be < O < N$.

Which of the following statements is correct?

Identify the incorrect order.

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