An element crystallises in a face-centred cub | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In an $fcc$ unit cell,octahedral voids $(O.V.)$ are located at the centre of each edge and at the body centre.The distance between two nearest oct

Vedclass · Accepted Answer

$\frac{a}{\sqrt{2}}$

Vedclass · Answer

(C) In an $fcc$ unit cell,octahedral voids $(O.V.)$ are located at the centre of each edge and at the body centre.The distance between two nearest octahedral voids located at the centres of two adjacent edges is calculated using the Pythagorean theorem.The coordinates of the octahedral voids at the centres of two adjacent edges (e.g.,at $(a/2, 0, 0)$ and $(0, a/2, 0)$) result in a distance of:$d = \sqrt{(\frac{a}{2} - 0)^2 + (0 - \frac{a}{2})^2 + (0 - 0)^2}$$d = \sqrt{(\frac{a}{2})^2 + (\frac{a}{2})^2}$$d = \sqrt{\frac{a^2}{4} + \frac{a^2}{4}} = \sqrt{\frac{2a^2}{4}} = \sqrt{\frac{a^2}{2}} = \frac{a}{\sqrt{2}}$

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge $a$. The distance between the centres of two nearest octahedral voids in the crystal lattice is

Similar Questions

$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is

In $F.C.C.$,each face of the unit cell is shared equally by how many unit cells?

Coordination number of $Na^{+}$ ion in rock salt is

Body centered cubic lattice has a coordination number of

The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites is $A_{x}B$. The value of $x$ is ..... .
(Integer answer)

Vedclass Test Series

Exam Paper Generator

Online Exam Module