An element has a body-centered cubic structur | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a body-centered cubic $(bcc)$ structure, the number of atoms per unit cell $(Z)$ is $2$.Given edge length $(a)$ = $400 \ pm = 400 	imes 10^{-

Vedclass · Accepted Answer

$1.25$

Vedclass · Answer

(D) For a body-centered cubic $(bcc)$ structure, the number of atoms per unit cell $(Z)$ is $2$.Given edge length $(a)$ = $400 \ pm = 400 	imes 10^{-10} \ cm = 4 	imes 10^{-8} \ cm$.Atomic mass $(M)$ = $24 \ g \ mol^{-1}$.Avogadro's number $(N_A)$ = $6 	imes 10^{23} \ mol^{-1}$.The formula for density $(d)$ is:$d = \frac{Z 	imes M}{a^3 	imes N_A}$Substituting the values:$d = \frac{2 	imes 24}{(4 	imes 10^{-8})^3 	imes 6 	imes 10^{23}}$$d = \frac{48}{64 	imes 10^{-24} 	imes 6 	imes 10^{23}}$$d = \frac{48}{384 	imes 10^{-1}}$$d = \frac{48}{38.4} = 1.25 \ g \ cm^{-3}$.

An element has a body-centered cubic structure with a unit cell edge length of $400 \ pm$. The atomic mass of the element is $24 \ g \ mol^{-1}$. What is the density of the element (in $g \ cm^{-3}$)? $(N_{A} = 6 \times 10^{23} \ mol^{-1})$

Similar Questions

In the $x$-ray reflection $(n=1)$, the distance between two parallel planes of $NaCl$ is $280 \ pm$ and the diffraction angle is $5.2^{\circ}$. What is the wavelength of its light radiation? (Given: $\sin 5.2^{\circ} = 0.09$)

Calculate the number of atoms present in a unit cell for an element having a molar mass of $23 \ g \ mol^{-1}$ and a density of $0.96 \ g \ cm^{-3}$. Given that $a^3 \cdot N_{A} = 48 \ cm^3 \ mol^{-1}$.

Silver forms a $CCP$ structure and its density is $10.5 \ g/cm^3$. What is the edge length of the unit cell? (Molar mass of silver is $107.9 \ g/mol$)

How many unit cells are present in $39 \ g$ of potassium that crystallizes in a body-centred cubic structure? $[At. \ wt. \ of \ K = 39]$

If the radii of $Na^{+}$ and $Cl^{-}$ are $95 \, pm$ and $181 \, pm$ respectively, then the edge length of the $NaCl$ unit cell is equal to ...... $pm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module