An engine operating between temperatures $T_1$ and $T_2$ has efficiency $\eta = \frac{1}{5}$. When $T_2$ is lowered by $45 \ K$,its efficiency becomes $\eta' = \frac{1}{2}$. Temperatures $T_1$ and $T_2$ are respectively:

  • A
    $100 \ K, 70 \ K$
  • B
    $160 \ K, 120 \ K$
  • C
    $140 \ K, 110 \ K$
  • D
    $150 \ K, 120 \ K$

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