An experiment is set up as shown. Flasks 1 an | vedclass

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(B) Step $1$: Flask $1$ receives atmospheric air, which contains a very low concentration of $CO_2$. Therefore, the lime water in Flask $1$ remains cl

Vedclass · Accepted Answer

$(b)$

Vedclass · Answer

(B) Step $1$: Flask $1$ receives atmospheric air, which contains a very low concentration of $CO_2$. Therefore, the lime water in Flask $1$ remains clear.Step $2$: The air then passes through a germinating seed chamber (implied in this standard respiration experiment) where the seeds perform respiration and release $CO_2$.Step $3$: This $CO_2$-rich air enters Flask $2$. $CO_2$ reacts with lime water $(Ca(OH)_2)$ to form calcium carbonate $(CaCO_3)$, which is insoluble and turns the solution milky or cloudy.Step $4$: Thus, Flask $1$ remains clear and Flask $2$ becomes white/cloudy. The correct option is $(b)$.

Option	Flask $1$	Flask $2$
$(a)$	Clear	Clear
$(b)$	Clear	White/ Cloudy
$(c)$	White/ Cloudy	Clear
$(d)$	White/ Cloudy	White/ Cloudy

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