An ideal gas goes from state A to state B via | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The change in internal energy $(\Delta U)$ is a state function,meaning it is path-independent and depends only on the initial and final states.Sin

Vedclass · Accepted Answer

$Q_1 > Q_2 > Q_3$ and $\Delta U_1 = \Delta U_2 = \Delta U_3$

Vedclass · Answer

(D) The change in internal energy $(\Delta U)$ is a state function,meaning it is path-independent and depends only on the initial and final states.Since the initial state $A$ and final state $B$ are the same for all three processes,the change in internal energy is identical for all:$\Delta U_1 = \Delta U_2 = \Delta U_3$The work done $(W)$ by the gas in a $P-V$ diagram is equal to the area under the curve.From the given diagram,the area under curve $1$ is the largest,followed by curve $2$,and then curve $3$ is the smallest.Therefore,$W_1 > W_2 > W_3$.According to the first law of thermodynamics,$Q = \Delta U + W$.Since $\Delta U$ is constant for all processes and $W_1 > W_2 > W_3$,it follows that the heat absorbed must satisfy:$Q_1 > Q_2 > Q_3$

Similar Questions

An indicator diagram is a ...........

The pressure $(P)$ versus density $(d)$ graph of an ideal gas is shown in the figure. Choose the correct statement.

An ideal monoatomic gas is taken round the cycle $12341$ shown in the figure ($p-V$ diagram). The work done in one cycle is (in $P_0V_0$)?

$A$ thermodynamic system undergoes a cyclic process $PQRSP$. The total work done by the system is..... $J$.

The given diagram shows four processes,i.e.,isochoric,isobaric,isothermal,and adiabatic. The correct assignment of the processes,in the same order,is given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module