An ideal gas undergoes a reversible isotherma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) From state $I$ to $II$ (Reversible isothermal expansion):$p$ decreases,$V$ increases,$T$ is constant.$H$ is constant (as $H = f(T)$ for an ideal g

Vedclass · Accepted Answer

$A, B, D$

Vedclass · Answer

(A) From state $I$ to $II$ (Reversible isothermal expansion):$p$ decreases,$V$ increases,$T$ is constant.$H$ is constant (as $H = f(T)$ for an ideal gas) and $S$ increases.From state $II$ to $III$ (Reversible adiabatic expansion):$p$ decreases,$V$ increases,$T$ decreases.$H$ decreases (as $T$ decreases) and $S$ is constant (reversible adiabatic process is isentropic).Analysis of plots:$(A)$ $p$ vs $V$: Correct,both processes show $p$ decreasing as $V$ increases.$(B)$ $p$ vs $T$: Correct,$T$ is constant from $I$ to $II$ ($p$ decreases),then $T$ decreases from $II$ to $III$ ($p$ decreases).$(C)$ $H$ vs $S$: Incorrect,$H$ should decrease from $II$ to $III$ while $S$ remains constant.$(D)$ $T$ vs $S$: Correct,$T$ is constant from $I$ to $II$ ($S$ increases),then $T$ decreases from $II$ to $III$ ($S$ is constant).Therefore,the correct plots are $(A), (B), (D)$.

Similar Questions

For the reaction $2 Cl ( g ) \rightarrow Cl _{2}( g )$,the correct option is

How many quantities have a similar unit as molar entropy?
$(i)$ Heat capacity
$(ii)$ Molar heat capacity
$(iii)$ Universal gas constant
$(iv)$ Specific heat capacity

The enthalpy of vaporization of a liquid at $500 \, K$ and $1 \, atm$ pressure is $10 \, kcal \, mol^{-1}$. The change in internal energy $(\Delta U)$ for $3 \, moles$ of the liquid at the same temperature and pressure is ............ $kcal$.

For the reaction $2A_{(g)} + B_{(g)} \to 2D_{(g)}$,given $\Delta U^{\theta} = -10.5 \ kJ$ and $\Delta S^{\theta} = -44.1 \ J \ K^{-1}$. Calculate $\Delta G^{\theta}$ for the reaction at $298 \ K$ and predict whether the reaction may occur spontaneously.

The value of $\Delta H$ for cooling $2 \ mol$ of an ideal monoatomic gas from $225^{\circ} C$ to $125^{\circ} C$ at constant pressure will be [given $C_{p} = \frac{5}{2} R$]. (in $R$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module