An inductor is connected to an AC source of f | vedclass

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(C) For an $AC$ circuit containing an inductor only:$I = I_0 \sin(\omega t)$$V = V_0 \sin(\omega t + \frac{\pi}{2}) = V_0 \cos(\omega t)$Instantaneous

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$100$

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(C) For an $AC$ circuit containing an inductor only:$I = I_0 \sin(\omega t)$$V = V_0 \sin(\omega t + \frac{\pi}{2}) = V_0 \cos(\omega t)$Instantaneous power $P = V \cdot I$$P = (V_0 \cos(\omega t)) \cdot (I_0 \sin(\omega t))$Using the trigonometric identity $\sin(2	heta) = 2 \sin(	heta) \cos(	heta)$:$P = \frac{V_0 I_0}{2} \sin(2\omega t)$The angular frequency of the power is $2\omega$. Since $\omega = 2\pi f$,the frequency of the power $f' = 2f$.Given $f = 50 \ Hz$,the frequency of the instantaneous power is $f' = 2 	imes 50 \ Hz = 100 \ Hz$.

An inductor is connected to an $AC$ source of frequency $50 \ Hz$. The frequency of the instantaneous power developed in the circuit is (in $Hz$)

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