An inductor of inductance 2 , mH is connected | vedclass

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(C) For an $AC$ source,the inductive reactance is given by $X_L = \omega L = 2 \pi f L$.Given $L = 2 \, mH = 2 	imes 10^{-3} \, H$ and $f = 50 \, Hz$

Vedclass · Accepted Answer

$0.628 \, \Omega$,zero

Vedclass · Answer

(C) For an $AC$ source,the inductive reactance is given by $X_L = \omega L = 2 \pi f L$.Given $L = 2 \, mH = 2 	imes 10^{-3} \, H$ and $f = 50 \, Hz$.$X_1 = 2 	imes \pi 	imes 50 	imes 2 	imes 10^{-3} = 100 \pi 	imes 2 	imes 10^{-3} = 0.2 \pi \, \Omega$.Using $\pi \approx 3.14$,we get $X_1 = 0.2 	imes 3.14 = 0.628 \, \Omega$.For a $DC$ source,the frequency $f = 0$,so the angular frequency $\omega = 2 \pi f = 0$.The inductive reactance $X_2 = \omega L = 0 	imes L = 0 \, \Omega$.Thus,$X_1 = 0.628 \, \Omega$ and $X_2 = 0$.

An inductor of inductance $2 \, mH$ is connected to a $220 \, V, 50 \, Hz$ $AC$ source. Let the inductive reactance in the circuit be $X_1$. If a $220 \, V$ $DC$ source replaces the $AC$ source in the circuit,then the inductive reactance in the circuit is $X_2$. $X_1$ and $X_2$ respectively are:

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