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(A) Initial potential energy of the ball at height $H = 100 \ m$ is $E_i = mgH = mg(100)$.After the collision with the earth,the ball loses $20 \%$ of

Vedclass · Accepted Answer

$80$

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(A) Initial potential energy of the ball at height $H = 100 \ m$ is $E_i = mgH = mg(100)$.After the collision with the earth,the ball loses $20 \%$ of its energy.Therefore,the remaining energy $E_f$ of the ball is $80 \%$ of the initial energy.$E_f = 0.80 	imes E_i = 0.80 	imes mg(100) = 80mg$.Let the ball rise to a new height $h$ after the collision.The potential energy at this new height is $E_f = mgh$.Equating the energies: $mgh = 80mg$.Dividing both sides by $mg$,we get $h = 80 \ m$.

An inelastic ball is dropped from a height of $100 \ m$. Due to collision with the earth,$20 \%$ of its energy is lost. To what height will the ball rise?

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