An iron bar of length 10, m is heated from 0^ | vedclass

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(B) The formula for the increase in length due to thermal expansion is given by $\Delta L = L_0 \alpha \Delta 	heta$.Here,the initial length $L_0 = 1

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$1.0$

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(B) The formula for the increase in length due to thermal expansion is given by $\Delta L = L_0 \alpha \Delta 	heta$.Here,the initial length $L_0 = 10\, m$,the coefficient of linear expansion $\alpha = 10 	imes 10^{-6} {^{\circ}C^{-1}}$,and the change in temperature $\Delta 	heta = 100^{\circ}C - 0^{\circ}C = 100^{\circ}C$.Substituting these values into the formula:$\Delta L = 10 	imes (10 	imes 10^{-6}) 	imes 100$$\Delta L = 10 	imes 10^{-5} 	imes 100 = 10^{-2}\, m$.Since $1\, m = 100\, cm$,we have $\Delta L = 10^{-2} 	imes 100 = 1\, cm$.Therefore,the increase in the length of the bar is $1.0\, cm$.

An iron bar of length $10\, m$ is heated from $0^{\circ}C$ to $100^{\circ}C$. If the coefficient of linear thermal expansion of iron is $10 \times 10^{-6} {^{\circ}C^{-1}}$,the increase in the length of the bar is .......... $cm$.

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