An isosceles right triangle has an area of 8 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the two equal sides of the isosceles right triangle be $a \, cm$. The area of the triangle is given by $\frac{1}{2} 	imes 	ext{base} 	imes

Vedclass · Accepted Answer

$\sqrt{32} \, cm$

Vedclass · Answer

(B) Let the two equal sides of the isosceles right triangle be $a \, cm$. The area of the triangle is given by $\frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$. Since it is an isosceles right triangle,base $= a$ and height $= a$. Therefore,$\frac{1}{2} 	imes a 	imes a = 8$. $a^{2} = 16$,which gives $a = 4 \, cm$. By the Pythagorean theorem,the hypotenuse $h$ is given by $h = \sqrt{a^{2} + a^{2}} = \sqrt{4^{2} + 4^{2}} = \sqrt{16 + 16} = \sqrt{32} \, cm$.

An isosceles right triangle has an area of $8 \, cm^{2}$. The length of its hypotenuse is

Similar Questions

Find the area of the trapezium $PQRS$ with height $PQ$ given in the figure (in $m^2$).

In a quadrilateral $ABCD$,$AB = 29 \, cm$,$BC = 35 \, cm$,$CD = 14 \, cm$,$DA = 50 \, cm$ and $AC = 48 \, cm$. Find its area. (in $, cm^2$)

The sides of a quadrilateral $ABCD$ are $6 \, cm$,$8 \, cm$,$12 \, cm$,and $14 \, cm$ (taken in order) respectively,and the angle between the first two sides is a right angle. Find its area in $cm^2$.

Calculate the area of the shaded region in the figure.

$A$ rhombus-shaped sheet with a perimeter of $40 \, cm$ and one diagonal of $12 \, cm$ is painted on both sides at the rate of $Rs \, 5$ per $cm^2$. Find the cost of painting (in $Rs$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module