An oblong piece of ground measures 19 meters | vedclass

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(D) The dimensions of the ground are $19.25$ $m$ and $12.5$ $m$ (since $1$ $dm = 0.1$ $m$).There are two paths: one parallel to the length and one par

Vedclass · Accepted Answer

$733.04$

Vedclass · Answer

(D) The dimensions of the ground are $19.25$ $m$ and $12.5$ $m$ (since $1$ $dm = 0.1$ $m$).There are two paths: one parallel to the length and one parallel to the width.The area of the path parallel to the length is $19.25 	imes 2 = 38.5$ $m^2$.The area of the path parallel to the width is $12.5 	imes 2 = 25$ $m^2$.The intersection of these two paths is a square of side $2$ $m$,which has been counted twice. Its area is $2 	imes 2 = 4$ $m^2$.Total area of the paths $= 38.5 + 25 - 4 = 59.5$ $m^2$.Cost of paving $= 59.5 	imes 12.32 = Rs. 733.04$.

An oblong piece of ground measures $19$ $meters$ $2.5$ $dm$ by $12$ $meters$ $5$ $dm$. From the centre of each side,a path $2$ $meters$ wide goes across to the centre of the opposite side. Find the cost of paving these paths at the rate of $Rs.$ $12.32$ per $sq$ $meter$. (in $Rs.$)

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